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ArrAy.CopyoF

首先观察先System.arraycopy(Object src, int srcPos, Object dest, int destPos, int length)的声明:[java] view plaincopypublic static native void arraycopy(Object src, int srcPos, Object dest, int destPos, int length); src - 源数组. srcPos - 源数组中

int[] a = {1,2,3};int[] b = java.util.Arrays.copyOf(a, 10);for(int s : a){System.out.println("原数组元素:"+s);}for(int s : b){System.out.println("新数组元素:"+s);}

楼主,你的打印有问题,,,,,,,d[]才是你要打印的 , a[]/b[]/c[] 都不是

astype实现变量类型转换:astype(type): returns a copy of the array converted to the specified type. a = a.astype('Float64') b = b.astype('Int32')

public static void arraycopy(Object src, int srcPos, Object dest, int destPos, int length)Parameters:src - the source array.源数据srcPos - starting position in the source array.起始下标dest - the destination array.目标源destPos - starting position in the

直接赋值,如{1,2,3} new方法

Arrays类的常用方法:1、boolean equals(array1,array2):比较两个数组是否相等.package com.jredu.ch06; import java.util.Arrays; public class Ch03 { public static void main(String[] args) { // TODO Auto-generated method stub String[] str1={"1"

C语言中复制数组的内容源代码如下:#include <stdio.h>#include <string.h>#include <stdlib.h>#define SIZE 10 void show_array(const int ar[], int n); int main() { int values[SIZE] = {1,2,3,4,5,6,7,8,9,10}; int target[SIZE]; double curious[SIZE / 2] = \ {2.0

java的多维数组的copy:希望采纳class C{ public static void main(String args[]){ int a[][] = {{1,2,3},{4,5,6}}; int b[][] = new int[a.length][a[0].length]; System.arraycopy(a,0,b,0,a.length); //通过arraycopy()函数拷贝数组 b[0][0] = 4; //改变数组b[0][0]的值 System.out.println("a[][]"); for(int i=0;i 评论0 0 0

copyOfpublic static int[] copyOf(int[] original, int newLength) 复制指定的数组,截取或用 0 填充(如有必要),以使副本具有指定的长度.对于在原数组和副本中都有效的所有索引,这两个数组将包含相同的值.对于在副本中有效而在原数组无

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