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python字典遍历vAluE

递归.用这个函数把dict里面的所有value用递归的方法提取到一个空list里面def dict2flatlist(d,l): print(d) for x in d.keys(): if type(d[x]) == dict: dict2flatlist(d[x],l) else: l.append(d[x])d = {1:"a",2:"b",3:{4:"c",5:"d",6:{7:"e"}},8:"f"}l = []dict2flatlist(d,l)print(l)希望对你有帮助

不知道你是不是这个意思,字典调用values()方法会返回Value值所构成的列表,通过两个循环就能遍历字典里的列表data = {'a':[1,2,3],'b':[4,5,6]}for l in data.values(): for item in l: print item

dic = {"1":"a,b,c", "2":"d"} for k, v in dic.items():valus = v.split(",") for value in values:print k, value

遍历其中一个字典的Key,然后替换就行了:代码如下:A = {'a': [1, 2], 'b': [3, 4]} B = {'a': 'x', 'b': 'y'} print('字典A的值: ', A) print('字典B的值: ', B) for key in A.keys(): B[key] = A[key] print('字典B就变成了A: ', B) 运行结果如下:

如题,例子是asin = [{'asin': b2b}] 取出其中的value,使用如下代码就可以了[item[key] for item in asin for key in item]

for key in e: for value in e[key]: print value

before = { "key1": 5, "key2": 6, "key3": 4, "key4": 3,}# 排序 after = dict(sorted(before.items(), key=lambda e: e[1])) print(after)# 取出前几个, 也可以在sorted返回的list中取前几个 cnt = 0 for key, value in after.items(): cnt += 1 if cnt > required_cnt: break print("{}:{}".format(key, value))

首先实现Python中遍历字典序列:d = {'Liu' : 24,'Zhang' :25,'Chen' : 23}for name in d:print name+"'s age is",d[name]>>Chen's age is 23>>Liu's age is 24>>Zhang's age is 25如上结果所示可以实现遍历,作为一个Python新手,我注意到在单引

#dict的values()方法,可以遍历也可以直接in判断是否存在 a = {'a':1, 'b':2, 'c':3} if 4 in a.values(): print('exit')

def parse_dict(d):for key, value in d.items():if isinstance(value, dict):parse_dict(value)else:print keyprint valueprint '-----------'if __name__ == '__main__':a = {'a': {'b': 1}, 'c': 2}parse_dict(a)

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